Question

find the zeroes of the polymomial x^2 -3​

Answer 1

Answer:

Zeroes = √3 and -√3

Step-by-step explanation:

NOTE : Zeroes of a polynomial is defined as any real value of variable for which the value of polynomial becomes zero.

We know, INDENDITY :

=> a² - b²

=> ( a + b ) ( a - b )

Applying the identity to factorise :

=> x² - 3

=> ( x )² - ( √3 )²

=> ( x + √3 ) ( x - √3 )

=> ( x + √3 ) = 0 or

( x - √3 ) = 0

=> x = -√3 or

x = +√3

ANS) The zeroes of the polynomial are √3 and -√3

Thanks !

Answer 2

Given that ,

The polynomial is (x)² - 3

It can be written as ,

⇒(x)² - (√3)²

Using identity :

(a)² - (b)² = (a - b) (a + b)

⇒(x)² - (√3)²

⇒(x - √3) (x + √3)

⇒x = √3 or x = -√3

$\therefore \sf \underline{The \: zeroes \: of \: polynomial \: are \: \sqrt{3} \: and - \sqrt{3} }$