Math, asked by dhanyasajeesh2003, 10 months ago

Find the zeroes of the polynomial -18x²+3x+1

Answers

Answered by mhanifa

2

Answer:

-1/6 & 1/3

Step-by-step explanation:

Find the zeroes of the polynomial -18x²+3x+1

-18x²+3x+1=0
18x²-3x-1=0
18x² - 6x + 3x - 1=0
6x(3x-1)+(3x-1)=0
(6x+1)(3x-1)=0
6x+1=0 => 6x=-1 => x= -1/6

3x-1=0 => 3x=1 => x=1/3

Zeroes of polynomial are: -1/6 and 1/3

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