Question

Find the zeroes of the polynomial 2 x 3 + 5 x 2 – 23 x + 10.

Answer 1

Answer:

2x3-5x2-23x-10=0

Three solutions were found :

x = 5

x = -2

x = -1/2 = -0.500

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((2 • (x3)) - 5x2) - 23x) - 10 = 0

Step 2 :

Equation at the end of step 2 :

((2x3 - 5x2) - 23x) - 10 = 0

Step 3 :

Checking for a perfect cube :

3.1 2x3-5x2-23x-10 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2x3-5x2-23x-10

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -23x-10

Group 2: 2x3-5x2

Pull out from each group separately :

Group 1: (23x+10) • (-1)

Group 2: (2x-5) • (x2)