Question

find the zeroes of the polynomial 2x^2+7x-4

Answer 1

$hey \: mate \: here \: is \: your \: answer$
$2x {}^{2} + 7x - 4$
$2x {}^{2} + (8 - 1)x - 4$
$2x {}^{2} + 8x - x - 4$
$2x(x + 4) - 1(x + 4)$
$(2x - 1)(x + 4)$
$hope \: it \: helps.....$

Answer 2

Bonjour!

2x² + 7x - 4
2x² - x + 8x - 4
x(2x - 1) + 4(2x - 1)
(x + 4) (2x - 1) are factors of the given polynomial

For zeroes
x+4=0
x = -4

2x-1=0
x = ½

Hence, the zeroes are -4 and 1/2.

I hope this answer helped you.