Question

What are the three consecutive multiples of 7 is 63 find these multiples

Answer 1

Heya!Here is your answer friend ⏬
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Let the consecutive mutiples be X, X+7 and X+14 respectively.

There sum is given 63.

$x + x + 7 + x + 14 = 63 \\ 3x + 7 + 14 = 63 \\ 3x = 63 - 21 \\ 3x = 42 \\ x = \ \frac{42}{3} = 14$
Hence the multiples are 14, 21 and 28.

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Answer 2

Let one of the three multiple is " x "

Then the other two multiples are " x + 7 , x + 14 " .

Now, Given that The sum of the three consecutive multiples of 7 is 63 .

So,

$\boxed{ \:x +( x + 7) +(x + 14) = 63 } \\ \\ x + x + x + (7 + 14) = 63 \\ \\ 3x + 21 = 63 \\ \\ 3x = 63 - 21 \\ \\ 3x = 42 \\ \\ x = \frac{42}{3} = 14$

$Now \: , The \: three \: consecutive \: \\ multiples \: are \: \\ \\ x = 14 \\ x + 7 = 21 \\ x + 14 = 28$

$\large{ \mathbf{ Therefore \: , The \: three \: consecutive \: multiples \: of \: 7 \: whose \: sum \: equals \: 63 \: are \: 14 , 21 , 28}}$