Question

find the zeroes of the polynomial 2x^2-8x+6

please answer fast very urgent
thankyou in advance:)

Answer 1

Hey friend

Here is your answer

=2x²-8x+6

=2(x²-4x+3)

=x²-4x+3

=x²-x-3x+3

=x(x-1)-3(x-1)

=(x-3)(x-1)

x-3=0

x=3

x-1=0

x=1

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THE ZEROES OF THE POLYNOMIAL ARE 3 AND 1

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HOPE THIS HELPS YOU ☺

Answer 2

Answer:

the solution are 3 and 1

Step-by-step explanation:

Given : $2x^2-8x+6=0$

To Find : x

Solution:

$2x^2-8x+6=0$

$2(x^2-4x+3)=0$

$x^2-4x+3=0$

$x^2-x-3x+3=0$

$x(x-1)-3(x-1)=0$

$(x-3)(x-1)=0$

$x-3=0$

$x=3$

$x-1=0$

$x=1$

Thus the solution are 3 and 1