Question

Find the zeroes of the polynomial 3√3x² -19x +10√3

Answer 1

Hello friend

Your answer is given below

$= > p(x) = 3 \sqrt{3} {x}^{2} - 19x + 10 \sqrt{ 3 } \\ \\ = > 3 \sqrt{3} {x}^{2} - 19x + 10 \sqrt{3} \\ \\ = > 3 \sqrt{3} {x}^{2} - 10x - 9x + 10 \sqrt{3} \\ \\ = > 1x(3 \sqrt{3} x - 10) - \sqrt{3} (3 \sqrt{3} x - 10) \\ \\ = > (x - \sqrt{3} )(3 \sqrt{3} x - 10) \\ \\ = > x = \sqrt{3} \: \: and \: x \: = \frac{10}{3 \sqrt{3} }$

I hope it will help you a lot

Thanks

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