Find the zeroes of the polynomial √3x2-8x+4√3
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Let f(x) = √3x2+ 8x + 4√3
√3x2+ 8x + 4√3 = 0
√3x2+ 6x + 2x + 4√3 = 0
√3x(x + 2√3) + 2(x + 2√3) = 0
(x + 2√3)(√3x + 2) = 0
x + 2√3 = 0 or √3x + 2 = 0
x = -2√3 or x = -2/√3
So, the zeroes of √3x2+ 8x + 4√3 are -2√3 and -2/√3
√3x2+ 8x + 4√3 = 0
√3x2+ 6x + 2x + 4√3 = 0
√3x(x + 2√3) + 2(x + 2√3) = 0
(x + 2√3)(√3x + 2) = 0
x + 2√3 = 0 or √3x + 2 = 0
x = -2√3 or x = -2/√3
So, the zeroes of √3x2+ 8x + 4√3 are -2√3 and -2/√3
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