find the zeroes of the polynomial √3x²-8x+4√3
gdfvirx:
2/root3,2root3
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Answer:
x = 2/√3 , x = 2√3
Step-by-step explanation:
√3x² - 8x + 4√3
First factories this equation.......
=>√3x² - 6x - 2x + 4√3
=> √3x(x - 2√3) -2(x - 2√3)
=> (√3x - 2)(x - 2√3)
=> √3x - 2 = 0 , x - 2√3 = 0
=> x = 2/√3 , x = 2√3
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