Math, asked by angelaguha47, 1 year ago

find the zeroes of the polynomial √3x²-8x+4√3


gdfvirx: 2/root3,2root3

Answers

Answered by Anonymous
14

Answer:

x = 2/√3 , x = 2√3

Step-by-step explanation:

√3x² - 8x + 4√3

First factories this equation.......

=>√3x² - 6x - 2x + 4√3

=> √3x(x - 2√3) -2(x - 2√3)

=> (√3x - 2)(x - 2√3)

=> √3x - 2 = 0 , x - 2√3 = 0

=> x = 2/√3 , x = 2√3


mansipatel5: hi
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