Find the zeroes of the polynomial 3xcube-10xsquare+9x-2.
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Answer:
(x-1) (x-2) (3x-1)
Step-by-step explanation:
By hit and trial method, we see that if we substitute 1 at place of x, the value of the polynomial will be 0.
So, (x-1) is a factor of the polynomial.
3x³-10x²+9x-2
= 3x³-3x²-7x²+7x+2x-2
= 3x²(x-1)-7x(x-1)+2(x-1)
= (x-1) (3x²-7x+2)
= (x-1) {3x²-6x-x+2}
= (x-1) {3x(x-2)-1(x-2)}
= (x-1) (x-2) (3x-1)
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