Question

Find the zeroes of the polynomial 3xcube-10xsquare+9x-2.​

Answer 1

Answer:

(x-1) (x-2) (3x-1)

Step-by-step explanation:

By hit and trial method, we see that if we substitute 1 at place of x, the value of the polynomial will be 0.

So, (x-1) is a factor of the polynomial.

3x³-10x²+9x-2

= 3x³-3x²-7x²+7x+2x-2

= 3x²(x-1)-7x(x-1)+2(x-1)

= (x-1) (3x²-7x+2)

= (x-1) {3x²-6x-x+2}

= (x-1) {3x(x-2)-1(x-2)}

= (x-1) (x-2) (3x-1)