Question

find the zeroes of the polynomial 4√3 x²+4√3x-3√3

Answer 1

ANSWER:

• Zeros are 1/2 and -3/2.

GIVEN:

• P(x) = 4√3x²+4√3x-3√3

TO FIND:

• Zeros of the polynomial.

SOLUTION:

=> 4√3x²+4√3x-3√3 = 0

=> 4√3x²+6√3x-2√3x-3√3 = 0

=> (4√3x²+6√3x)+(-2√3x-3√3) = 0

=> 2√3x(2x+3)-√3(2x+3) = 0

=> (2x+3)(2√3x-√3) = 0

Either (2x+3) = 0

=> 2x = -3

=> x = -3/2

Either (2√3x-√3) = 0

=> 2√3x = √3

=> x = 1/2

Zeros are 1/2 and -3/2.

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab