Question

find the zeroes of the polynomial 4 x²-12x+9

Answer 1

${4x}^{2} - 12x + 9 \\ {4x}^{2} - 6x - 6x + 9 \\ 2x(2x - 3) - 3(2x - 3) \\ (2x - 3)(2x - 3) \\ \\ \\ (2x - 3)(2x - 3) = 0 \\ 2x - 3 = 0 \: or \: 2x - 3 = 0 \\ x = \frac{ 3}{2} \: or \: x = \frac{3}{2} \\ \\ \alpha = \frac{3}{2} \: and \: \beta = \frac{3}{2}$