find the zeroes of the polynomial 4rrot3 x^2+5x-2root3
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=4√3x²+5x-2√3
=4√3x²+(8-3)x-2√3
=4√3x²+8x-3x-2√3
=4x(√3x+2)-√3(√3x+2)
=(4x-√3)(√3x+2)
4x-√3=0
x=√3/4
√3x+2=0
x=-2/√3
=4√3x²+(8-3)x-2√3
=4√3x²+8x-3x-2√3
=4x(√3x+2)-√3(√3x+2)
=(4x-√3)(√3x+2)
4x-√3=0
x=√3/4
√3x+2=0
x=-2/√3
suzna:
thank uh it helped me a lot
ur welcome
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