Find the zeroes of the polynomial 4x?+5root2x-3
Answers
Answered by
265
4x² +5√2 x -3 =0
⇒4x² +6√2 x -√2 x -3 =0
⇒2√2x(√2x+3) -1(√2x+3) =0
⇒(√2x+3)(2√2x -1) =0
⇒(√2 x+3) = 0 or (2√2x -1) =0
⇒x = -3/√2 or 1/2√2
or x = = (3√2)/2 and (√2)/4
⇒4x² +6√2 x -√2 x -3 =0
⇒2√2x(√2x+3) -1(√2x+3) =0
⇒(√2x+3)(2√2x -1) =0
⇒(√2 x+3) = 0 or (2√2x -1) =0
⇒x = -3/√2 or 1/2√2
or x = = (3√2)/2 and (√2)/4
Answered by
67
Answer:
Step-by-step explanation:
✒4x²+5√2x-3
✒4x²+6√2x-√2x
✒2√2x(√2x+3)-1(√2x+3)
✒(√2x+3)(2√2x+3)
ZerØè$ are⤵⤵
✒√2x+3=0. ✒2√2x-1=0
✒x=(-3)/√2. ✒x=1/2√2
✒ x=(-3√2)/2.✒x=√2/4
_______hope it helps=========SnehaG__reGàRds
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