Find the zeroes of the polynomial 6x3-7x2-11x 12, if x-1 is a factor of the polynomial
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45
(x - 1) • (3x + 4) • (2x - 3)
Answered by
47
answer:-
6x^3 - 7×x^2 - 11×1 + 12
=>f (x)= x-1
so, 6×1^3 - 7×1^2 - 11×1 + 12
=6-7-11+12
= -1+1
=0
SO THAT'S THE ANSWER AS MUCH I KNOW!
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