Question

Find the zeroes of the polynomial 8x^2+22x-6​

Answer 1

Answer:

Step-by-step explanation:

8x² + 22x - 6

⇒ 4x² + 11x - 3 = 0

⇒ 4x² +12x - x  - 3 = 0

⇒ 4x(x+3) -1( x+3) = 0

⇒ (4x - 1) (x + 3) = 0

4x - 1 = 0 : x + 3 = 0

x = 1/4  : x = -3

Hope it Helps You :)