Find the zeroes of the polynomial f(x) = underoot 3x^2 +5x -8underroot3 and verify the relationship between the zeroes and its coefficients.
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f(x) = √3x^2 +5 x -8√3
= √3x^2+8x-3x -8√3
=x(√3x+8) -(√3x+8)
=(√3x+8)(x-√3)
for zeros of f(x)
f(x) =0
(√3x+8)(x-√3)=0
x=-8/√3 or x=√3
sum of zeros=-5/√3
-8/√3+√3= -5/√3
-5/√3=-5/√3
product of zeros =-8√3/√3
-8/√3× √3= -8√3/√3
-8√3/√3=-8√3/√3
hence verified
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