Find the zeroes of the polynomial P of Y is equal to 7 y square minus 11 by 3 Y - 2 by 3
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Answer:
7y² - 11y/3 - 2/3 = 0
=> 21y² - 11y - 2 = 0
=> 21y² + 3y - 14y - 2 = 0
=> 3y(7y + 1) - 2(7y + 1) = 0
=> (3y -2)(7y + 1) = 0
=> y = 2/3 or -1/7
Sum of roots = 2/3 - 1/7 = 11/21 = -b/a = - (-11/3 )/7 = 11/21
Products of roots = (2/3)(-1/7) = - 2/21 = c/a = (-2/3)/7 = - 2/21
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