Question

Find the zeroes of the polynomial : p(t) = (t 3)^ 2 (t + 3)^ 2

Answer 1

let pls t be x it will easy to me to insert in the formula pls

$p(x) = 3x {}^{2} \times (x + 3) {}^{2} = 0 \\ 3x {}^{2} \times (x {}^{2} + 6x + 9) = 0 \\ x {}^{2} + 6x + 9 = 0 \\ x {}^{2} + 3x + 3x + 9 = 0 \\ x(x + 3) + 3(x + 3) = 0 \\ (x + 3)(x + 3) = 0 \\ x = - 3 \\ x = - 3 \\ or \\ x {}^{2} + 6x + 9 = 0 \\ (x + 3) {}^{2} = 0 \\ (x + 3)(x + 3) = 0 \\ x = - 3 \\ x = - 3$

ans x=-3

x=-3

pls mark me as the brain list☺️