Question

find the zeroes of
the polynomial
(p) = (x-2)²-(x + 2)².


please give right answer.wrong answer would be reported.​

Answer 1

Answer:

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Step-by-step explanation:

Find zeros of polynomial p(x)=(x−2)

Find zeros of polynomial p(x)=(x−2) 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2)

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2)

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2)

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0x=0

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0x=0

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0x=0

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0x=0 Hence,

Find zeros of polynomial p(x)=(x−2) 2 −(x+2) 2P(x)=(x−2) 2 −(x−2) 2 This is in the form of a 2 −b 2 P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0x=0 Hence,x=0 is the zero of the polynomial P(x)

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Answer 2

Answer:

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