Find the zeroes of the polynomial p(x) = √3x2+2√3x+ √3
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√3x^2 +2√3x +√3 =0
√3x^2 -√3x -√3x +√3= 0
√3x(x-1) -√3(x-1)=0
(√3x-√3) (x-1)
x=√3/√3=1 or
x-1=0
x=1
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