Question

Find the zeroes of the polynomial: p(x)=5x2-3-2x.

Answer 1

Here is your solution :-

$5 {x}^{2} - 3 - 2x = 0 \\ \\ 5 {x}^{2} - 2x - 3 = 0 \\ \\ 5 {x}^{2} - 5x + 3x - 3 = 0 \\ \\ 5x \: (x - 1) + 3(x - 1) = 0 \\ \\ (x - 1) \: (5x + 3) = 0 \\ \\ x = 1 \: \: \: \: or \: \: \: x \: = \frac{ - 3}{5}$

Thank me later xD

Answer 2

Answer:

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