Question

Find the Zeroes of the Polynomial p(x) =
$\sqrt{2x2} + 7x + 5 \sqrt{2}$
and make Relationship with Zeroes and Coefficients.​

Answer 1

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Answer 2

Answer:

= √2$x$² + 7

= √2$x$² + 5

= √2$x$² +5

= $x$ (√2x + 5) + √2 (√2x + 5) = 0

= ($x$ + √2) = 0        

= ($x$ = -√2)  

= (√2$x$ + 5) = 0

= $x$ = -5/√2

= β = 5/√2

∴ ∝ = -√2 and β = 5/-√2

= √2$x$² + 7

= ∝ + β = -√2 + (-5/2)

= -√2 - 5/√2

= -2-5/√2 = -7/√2

= ∝β = (-√2) (-5/2)

= ∝ + β = -b/a

= -7/√2

= ∝β = c/a

= 5 √2/√2

= 5