Question

find the zeroes of the polynomial p(x)=x^2-3​

Answer 1

Answer:

=> $x^{2}$ = 3

=> x = + or - $\sqrt[]{3}$

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Answer 2

here is your answer mate...

we can also write this equation like this. X^2-roo3^2

Therefore by formula x^2-y^2=(x+y)(x-y)

we can write

(x+root 3)(x-root3)

therefore.. x= (-Root3) and (root 3)

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