Question

find the zeroes of the polynomial p(x)=x^3-5x^2+6x ( with out using the graph)​

Answer 1

Step-by-step explanation:

I hope it will help u ❤️

Answer 2

Step-by-step explanation:

p(x)=x^3-5x^2+6x

=x^3-3x^2-2x^2+6x

=x^2(x-3)- 2x (x-3)

=(x^2 - 2x) (x-3

=(x^2-2x)=0. (x-3)=0

x^2-2x=0. x = 3

x(x - 2)=0

x - 2=0

x=2

the zeros of the polynomial are 2 and 3