Question

find the zeroes of the polynomial
q(x)=x+4
h(x)=6x-1
p(x)=ax+b
r(x)=x²+3x
t(x)=x²+2x+1

Answer 1

q (x)= -4
h (x)= 1/6
p (x)= -b/a

Answer 2

1.x+4=0
x=-4
2. 6x-1=0
x=1/6
3. ax+b=0
x=-b/a
4. x^2+3x=0
x(x+3)=0
x=0,x=-3
5. x^2+2x+1
x^2+1x+1x+1
x (x+1)+1 (x+1)
(x+1)=0
x=-1.