Find the zeroes of the polynomial
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Hello friend
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Your answer is given in the attachment
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Good morning
Your answer is given in the attachment
I hope it will help you a lot
Thanks
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
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Heya !!!
(X -2)² - (X +2)²
=> ( X)² + (2)² - 2 × X × 2 - { ( X)² + (2)² + 2×X×2}
=> X² + 4 - 4X - ( X² + 4 + 4X )
=> X² + 4 - 4X - X² - 4 - 4X
=> -8X = 0
=> X = 0/-8
=> X = 0
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
(X -2)² - (X +2)²
=> ( X)² + (2)² - 2 × X × 2 - { ( X)² + (2)² + 2×X×2}
=> X² + 4 - 4X - ( X² + 4 + 4X )
=> X² + 4 - 4X - X² - 4 - 4X
=> -8X = 0
=> X = 0/-8
=> X = 0
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
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