Question

Find the zeroes of the polynomial :

( x-2 )² - ( x+2 )²

Answer 1

= (x - 2 + x + 2)(x - 2 - x - 2)
= (2x)(-4)
= -8x
So the zeroes of the polynomial is x = 0

Answer 2

it is in the form of a square - b square
which is equal to (a+b)(a-b)

so, (x-2 + x+2)(x-2-x+2)
(2x) (-4) = -8x
hence zeroes of the polynomial is x=0