particle starts moving at t=0 along a straight line with constant acceleration . the displacement s of the particle between t=n-1 sec and t=n sec is given by s=5+(0.2)n , where s is in meters
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is that a question
use two equations s1 = 0 + 1/2*a*(n-1)^2 and s2 = 0 + 1/2*a*(n^2)
subtract s2-s1 to get a
5+0.2n = 1/2a{n^2- (n-1)^2}
10+0.4n = a(n^2 - n^2 -1 +2n) = a(2n-1)
a = (10+0.4n)/(2n-1)
use two equations s1 = 0 + 1/2*a*(n-1)^2 and s2 = 0 + 1/2*a*(n^2)
subtract s2-s1 to get a
5+0.2n = 1/2a{n^2- (n-1)^2}
10+0.4n = a(n^2 - n^2 -1 +2n) = a(2n-1)
a = (10+0.4n)/(2n-1)
chandakaravali:
What you have done is right but you should compare the equations s=5+0.2n and s=an-a/2 , the coefficients of n will be equal i.e. a=0.2. ;) now we can find the rest.
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