Question

find the zeroes of the polynomial x^2+3x-4

Answer 1

x^2+3x-4 =0
x^2+4x-x-4=0
(x+4)(x-1)=0
So, x= 1,-4

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Answer 2

$= {x}^{2} + 3x - 4 \\ = {x}^{2} + 4x - x - 4 \\ = x(x + 4) - 1(x + 4) \\ = (x + 4)(x - 1)$

Therefore, two zeroes of the polynomial are -4 and 1.

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