find the zeroes of the polynomial x cube minus 6x square plus 12x minus 8 and (2) x cube plus 6x square plus 11x plus 6
Answers
Answer:
how we can find it I am not much brainear
Given : x³ - 6x² + 12x - 8 , x³ + 6x² + 11x + 6
To find : Zeroes
Solution:
x³ - 6x² + 12x - 8 = 0
x = 2
=> 8 - 24 + 24 -8 = 0
=> x - 2 is a factor
x³ - 6x² + 12x - 8 = (x - 2)(x² - 4x + 4)
(x² - 4x + 4) = 0
=> (x - 2)² = 0
=> x = 2
x³ - 6x² + 12x - 8 = (x - 2)³
zeroes are 2 ,
x³ + 6x² + 11x + 6
x = -1
=> -1 + 6 - 11 + 6 = 0
=> (x + 1) is a factor
x³ + 6x² + 11x + 6 = (x + 1)(x² + 5x + 6)
x² + 5x + 6 = 0
=> (x + 2)(x + 3) = 0
=> x = -2 , -3
Zeroes are - 1, -2 , - 3
Learn more:
The zeroes of polynomial root 3x square- 5x is - Brainly.in
https://brainly.in/question/17305270
Zeroes of a polynomial p(y) is______ of The point, where the graph ...
https://brainly.in/question/14676372
obtain all the zeros of the polynomial 8x^4+8x^3-18x^2-20x-5 if two ...
https://brainly.in/question/7286826