Question

Find the zeroes of the polynomial x² -√2x-12

Answer 1

Hey your answer is in the given attachment

HOPE IT IS HELPFUL

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Answer 2

Answer:

-2√2, 3√2

Step-by-step explanation:

x²-√2x-12

= x²+(2√2)x -(3√2)x -12

= x ( x+ 2√2) - 3√2( x+2√2)

= (x+2√2) ( x-3√2)

therefore zeroes of the given polynomial

= -2√2 , and 3√2