Question

when a die is thrown what is the probability of getting a prime number ​

Answer 1

Answer:

total outcomes = 6

favourable outcomes = {2,3,5}

= 3

p(prime numbers) = 3/6

=1/2

Answer 2

Hey !

Given,

Event is Getting prime number when a die is thrown.

Let it be denoted by E.

Let S be the Sample space

S = {1, 2, 3, 4, 5, 6}. [The dice can show up only from 'S']

n(S) = 6

Note the possibilities for E

E = {Prime Numbers in between 1-6} = {2, 3, 5}

n(E) = 3

From the definition of Probability,

P(E) is ratio of no. of chances of occurance of Event 'E' to the total values in the sample space.

i.e., P(E) = n(E)/n(S) = 3/6 = 1/2 = 0.5

Probability that the die shows up a prime number when it's rolled is 0.5 (or) 1/2.

Meowwww xD