Question

Find the zeroes of the polynomial x²-3 and verify the relationship between the zeroes and the coefficients .​

Answer 1

$\huge\bold\red{★Answer★}$

$given \: polynomial \: is \: {x}^{2} \: - \: 3 \\ Here, a=1,b=0  and c=−3</p><p> \\ {x}^{2} - 3 = (x - \sqrt{3)} (x - \sqrt{3} ) \\ So, \: the \: value \: of \: {x}^{2} - 3 \: is \: zero \: when \: x = \sqrt{3} \: or \: x = - \sqrt{3} \\ therefore \: the \: zeros \: of \: {x}^{2} - 3 \: are \: \sqrt{3} \: and \: - \sqrt{3} \\ now \: sum \: of \: zeros = \sqrt{3} - \sqrt{3} = 0 = 0 \div 1 = - b \div a \\ product  of zeroes = ( \sqrt{3} )( - \sqrt{3} ) = - 3 = - 3 \div 1 = c \div a \\ hence \: verified.........$

$\huge\mathfrak\pink{Hope \: it \: helps \: you!!}$

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