Find the zeroes of the polynomial x2 - 5 and verify the relation between the zeroes and the coefficients.
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Given polynomial is x
2
−5
Let the zeros be α,β. (α>β)
x
2
−5=0⇒x
2
=5⇒x=±
5
α=
5
,β=−
5
So, α+β=0,αβ=−5
The coefficient of x is zero ⇒α+β=0
(& of x
2
is 1).
Constant = αβ=−5
Hence verified.
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