Find the zeroes of the polynomial x2 -64
Answers
Answered by
4
x^2-64=0
x^2-8^2=0
(x+8)(x-8)=0
It gives to Zeroes which are 8,-8
x^2-8^2=0
(x+8)(x-8)=0
It gives to Zeroes which are 8,-8
Answered by
5
Answer:
x^2-64=0
x^2-8^2=0
(x+8)(x-8)=0
It gives to Zeroes which are 8,-8
Step-by-step explanation:
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