find the zeroes of the polynomial xsquare + 7x + 12
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Answered by
7
X^2+7x+12
=x^2+3x+4x+12
= x(x+3) +4(x+3)
=(x+3). (x+4)
Plese mark it as brainlist X=-3.........x=-4....✌✌✌
=x^2+3x+4x+12
= x(x+3) +4(x+3)
=(x+3). (x+4)
Plese mark it as brainlist X=-3.........x=-4....✌✌✌
Answered by
1
hey friend,
=) The given equation is :-
=) f(x) = x^2 +7x+12
for equation to have zero f(x) must me zero.
=) f(x) = 0
=) x^2 +7x+12=0
=) x^2 +3x + 4x + 12 =0
=) x(x+3) + 4(x+3) =0
=) (x+3)(x+4) =0
=) so , (x+3) =0 & (x+4) =0
=) x = -3 & x = -4
so required zeros are -3 & -4
______________________________
Hope it will help u.
=) The given equation is :-
=) f(x) = x^2 +7x+12
for equation to have zero f(x) must me zero.
=) f(x) = 0
=) x^2 +7x+12=0
=) x^2 +3x + 4x + 12 =0
=) x(x+3) + 4(x+3) =0
=) (x+3)(x+4) =0
=) so , (x+3) =0 & (x+4) =0
=) x = -3 & x = -4
so required zeros are -3 & -4
______________________________
Hope it will help u.
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