find the zeroes of the polynomial y²+y-5.
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Hi ,
Let p ( y ) = y² + y - 5
To find zeros we have to make p ( y ) = 0
y² + y - 5 = 0----( 1 )
compare above quadratic equation with
ay² + by + c = 0 we get ,
a = 1 , b = 1 , c = 5
discreaminant = D = b² - 4ac
D = 1² - 4 × 1 × 5
D = 1 - 20
D = -19
√D = ( √19 ) i ----( 2 )
By quadratic formula ,
y = [ -b ± √D ] / 2a
= [ -1 ± ( √19 ) i ] / 2
Therefore ,
zeroes of p ( y ) are [ -1 ± ( √19 ) i ] / 2
I hope this helps you.
:)
Let p ( y ) = y² + y - 5
To find zeros we have to make p ( y ) = 0
y² + y - 5 = 0----( 1 )
compare above quadratic equation with
ay² + by + c = 0 we get ,
a = 1 , b = 1 , c = 5
discreaminant = D = b² - 4ac
D = 1² - 4 × 1 × 5
D = 1 - 20
D = -19
√D = ( √19 ) i ----( 2 )
By quadratic formula ,
y = [ -b ± √D ] / 2a
= [ -1 ± ( √19 ) i ] / 2
Therefore ,
zeroes of p ( y ) are [ -1 ± ( √19 ) i ] / 2
I hope this helps you.
:)
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