Question

find the zeroes of the polynomial6x^2-√2-2​

Answer 1

$\huge\underline\color{red}\boxed{AnSwEr}$

by using quadratic formula

$\color{brown}\boxed{x=\frac{-b±\sqrt{{b}^{2}-4ac}}{2a}}$

where a = 6 b = √2 and c = -2

by putting value in formula

$x = \frac{ - (- \sqrt{2)}± \sqrt{ { \sqrt{2} }^{2} - 4(6) (- 2)} }{2 \times 6} \\ \\ x= \frac{ { \sqrt{2} }^{}± \sqrt{2 + 48} }{12} \\ \\ x = \frac{ \sqrt{2} ± \sqrt{50} }{12}$

Now from here there could be two case either

case 1 st

$x = \frac{ \sqrt{2} + 5\sqrt{2} }{12} \\ \\ x = \frac{ 5\sqrt{2} }{12} - - - - 1s \: root \:$

case 2

$x = \frac{ \sqrt{2} + - 5 \sqrt{2} }{12} \\ \\ x = \frac{ - 5 \sqrt{2} }{12} - - - - - - 2nd \: root \:$

$\huge\color{green}{exrta\:info}$

we vould also find root by

factorisaton methord

but it's complicated so we fined it by quractic formula

#this formula is only valid on quratic equation

hope it helps you

be brainly