Question

find the zeroes of the quadratic equation 4s²-4x+1

Answer 1

HI!

Answer :

1/2 and 1/2

Step-by-step explanation:

$4x^{2} - 4x + 1$ = 0

$4x^{2} - 2x - 2x + 1 = 0\\2x (2x - 1) - 1 (2x - 1) = 0\\(2x-1) (2x-1) = 0\\(2x-1) = 0\\2x = 1\\x = 1/2$

therefore,the zeroes are 1/2 and 1/2

Answer 2

Answer:

4x2-4x+1

4x2-2x-2x+1

2x(2x-1)-1(2x-1)

(2x-1)(2x-1)

x=1/2. x= 1/2

Verify:

alpha + beta. (alpha)(beta)

1/2+1/2. (1/2)(1/2)

2/2=1. 1/4