Find the zeroes of the quadratic eqution, x2-2x-8
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Answer:
4 and -2
Explanation:
Given equation,
⇒ x² - 2x - 8
We need to find the zeros of the given quadratic equation.
Method (i) :-
Splitting the middle term,
⇒ x² - 4x + 2x - 8
⇒ x(x - 4) + 2(x - 4)
⇒ (x - 4)(x + 2)
⇒ x = 4
⇒ x = -2
∴ The zeros of the given polynomial is 4 and -2
Method (ii) :-
By quadratic formula,
→ [-b ± √(-b)² - 4ac]/2a
Where,
- a = 1 ; b = -2 and c = -8
Substituting the values,
→ [-(-2) ± √(-2)² - 4(1)(-8)]/2(1)
→ [2 ± √4 + 32]/2
→ [2 ± √36]/2
→ [2 ± 6]/2
→ 8/2 or, -4/2
→ 4 or, -2
Hence, the zeros are 4 and -2.
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