Find the zeroes of the quadratic poly x2+7x+10
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Answer:
x²+7x+10
= x²+5x+2x+10
= x(x+5)+2(x+5)
= (x+5)(x+2)
Zeros of the polynomial are -5 and -2
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Answered by
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Answer:
-2, -5 are zeroes of the given polynomial
Step-by-step explanation:
x²+7x+10=0
By splitting the middle term,
x²+5x+2x+10=0
x(x+5)+2(x+5)=0
(x+2)(x+5)=0
a) x+2=0
x=-2
b)x+5=0
x=-5
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