Find the zeroes of the quadratic polynomial 2x2
– 7 x – 9 .
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Step-by-step explanation:
2x^2 -7x -9
first multiply constant term with x^2 term
-9*2x^2
-18x^2
now take factors for -18x^2
2x and -9x
[because when we multiply the factors we have to get -18x^2
and when we solve we have to get x term which is -7x
so factors satisfied the both conditions
as 2x*-9x =18x^2
and 2x-9x= -7x ]
now the equation can be written as
2x^2 +2x -9x -9=0
2x (x +1) -9(x+1) =0
x+1 =0, 2x-9=0
x= -1 and 2x=9
x=9/2
so zeroes of the given polynomial are -1 and 9/2
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