find the zeroes of the quadratic polynomial 3x² -2 and verify the relation between the zeroes and the coefficients
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Answered by
316
3x^2-2 is the given quadratic polynomial
To get zeroes of the polynomial we should equate to 'zero 0'
3x^2-2=0
3x^2=2
x^2=2/3
x=root of (2/3) (OR) -root of(2/3)
VERIFICATION :-
The relatin between zeroes and coefficients is
(i) Sum of zeroes=-(coefficient of x)/(coefficient of x^2)
Root (2/3)-root (2/3)=-0/3
0=0
(ii) Product of zeroes = constant / (coefficient of x^2)
Root of(2/3)×-root of(2/3)=-2/3
-[root of (2/3)]^2=-2/3
-2/3=-2/3
Hence verified
HOPE IT HELPS!!
To get zeroes of the polynomial we should equate to 'zero 0'
3x^2-2=0
3x^2=2
x^2=2/3
x=root of (2/3) (OR) -root of(2/3)
VERIFICATION :-
The relatin between zeroes and coefficients is
(i) Sum of zeroes=-(coefficient of x)/(coefficient of x^2)
Root (2/3)-root (2/3)=-0/3
0=0
(ii) Product of zeroes = constant / (coefficient of x^2)
Root of(2/3)×-root of(2/3)=-2/3
-[root of (2/3)]^2=-2/3
-2/3=-2/3
Hence verified
HOPE IT HELPS!!
Answered by
160
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