Find the zeroes of the quadratic polynomial √3x2
-8x+4√3.
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Answered by
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Step-by-step explanation:
let p(x)
=√3x²-8x+4√3
=√3x²-(2+6)x+4√3
=√3x²-2x-6x+4√3
=x(√3x-2)-2√3(√3+2)
=(√3x-2)(x-2√3)
for ZEROES
p(x)=0
(√3x-2)(x-2√3)=0.
if √3x-2=0
x=2/√3
if x-2√3=0
x=2√3
zeroes=2√3,2/√3
hope this helps you
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