the line passing through thee point (2, -a) and (a, -1) is perpendicular to the line x-10y=1 the value of a is?
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Given : the line passing through thee point (2, -a) and (a, -1) is perpendicular to the line x-10y=1
To find : value of a is
Solution:
Two line perpendicular to each other
then multiplication of their slope is - 1
Slope of line
x - 10 y = 1
=> 10y = x - 1
=> y = x/10 - 1/10
Comparing with y = mx + c
=> m = 1/10
Slope = 1/10
Slope of line passing through thee point (2, -a) and (a, -1)
=> (-1 -(-a))/(a - 2)
= (a - 1)/(a - 2)
(1/10)( (a - 1)/(a - 2) ) = - 1
=> a - 1 = 20 - 10a
=> 11a = 19
=> a = 19/11
Value of a = 19/11
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