find the zeroes of the quadratic polynomial 5x^2+8x-4 and verify the relationship between zeroes and coefficients of the polynomial.
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Answered by
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Hlo......
Here is ur answer......
Let f(x) =5x^2+8x-4 and a and b be its zeroes
Here a= 5, b= 8 and c= -4
5x^2+8x-4=0
5x^2 + 10x - 2x - 4 =0
5x(x+2)-2(x+2)=0
(x+2)(5x-2)=0
x+2=0 or x=2/5
So, the zeroes are a = -2 and b = 2/5
a+b=-2+2/5=-8/5
-b/a=-8/5
So, a+b=-b/a
ab=-2*2/5=-4/5
c/a=-4/5
So, ab=c/a
Hope it helps......plz mark as brainliest.
Here is ur answer......
Let f(x) =5x^2+8x-4 and a and b be its zeroes
Here a= 5, b= 8 and c= -4
5x^2+8x-4=0
5x^2 + 10x - 2x - 4 =0
5x(x+2)-2(x+2)=0
(x+2)(5x-2)=0
x+2=0 or x=2/5
So, the zeroes are a = -2 and b = 2/5
a+b=-2+2/5=-8/5
-b/a=-8/5
So, a+b=-b/a
ab=-2*2/5=-4/5
c/a=-4/5
So, ab=c/a
Hope it helps......plz mark as brainliest.
Marina2171:
hi
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5
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I hope it helps you........
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