Question

find the zeroes of the quadratic polynomial 6x2-3-7x and verify the relationship between the zeroes and co-efficients

Answer 1

here is your answer.
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Answer 2

6x² - 7x - 3 is of the form ax²+bx+c
a = 6 , b = -7 , c = -3

6x² - 7x - 3 = 0
6x² - 9x + 2x - 3 = 0
3x (2x-3) + 1(2x-3) = 0
(3x+1) (2x-3) = 0

=> 3x+1 = 0
x = -1/3

=> 2x-3 = 0
x = 3/2

the two zeroes are - ⅓ and
$\frac{3}{2}$

Relationship between zeroes and coefficients :

sum of zeroes = -1/3 + 3/2
= (-2+9)/6
= 7/6
= -(-7)/6
= -b/a = - x coefficient /x² coefficient

Product of zeroes = (-1/3)(3/2)
= -3/6
= c/a = constant/x² coefficient


hope it helps..!