Find the zeroes of the quadratic polynomial 6x3-3-7x and verify the relationship between the zeroes and the coefficient of the polynomial .
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Step-by-step explanation:
6x² - 7x - 3 is of the form ax²+bx+c
a = 6 , b = -7 , c = -3
6x² - 7x - 3 = 0
6x² - 9x + 2x - 3 = 0
3x (2x-3) + 1(2x-3) = 0
(3x+1) (2x-3) = 0
=> 3x+1 = 0
x = -1/3
=> 2x-3 = 0
x = 3/2
the two zeroes are - ⅓ and
Relationship between zeroes and coefficients :
sum of zeroes = -1/3 + 3/2
= (-2+9)/6
= 7/6
= -(-7)/6
= -b/a = - x coefficient /x² coefficient
Product of zeroes = (-1/3)(3/2)
= -3/6
= c/a = constant/x² coefficient
hope it helps..!
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