Question

Find the zeroes of the quadratic polynomial 6x3-3-7x and verify the relationship between the zeroes and the coefficient of the polynomial .

Answer 1

Step-by-step explanation:

6x² - 7x - 3 is of the form ax²+bx+c

a = 6 , b = -7 , c = -3

6x² - 7x - 3 = 0

6x² - 9x + 2x - 3 = 0

3x (2x-3) + 1(2x-3) = 0

(3x+1) (2x-3) = 0

=> 3x+1 = 0

x = -1/3

=> 2x-3 = 0

x = 3/2

the two zeroes are - ⅓ and

Relationship between zeroes and coefficients :

sum of zeroes = -1/3 + 3/2

= (-2+9)/6

= 7/6

= -(-7)/6

= -b/a = - x coefficient /x² coefficient

Product of zeroes = (-1/3)(3/2)

= -3/6

= c/a = constant/x² coefficient

hope it helps..!