Find the zeroes of the quadratic polynomial 9t²-6t+1 and
verify the relation between the zeroes & Coefficient.
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Answered by
0
Answer:
x=1/3,1/3.
Step-by-step explanation:
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Answered by
0
Answer
9t² - 6t + 1 = 0
⇒ 9t² - 3t - 3t + 1 = 0
⇒ 3t(3t-1) -1(3t-1) = 0
⇒ (3t-1)(3t-1)=0
⇒ (3t-1)² = 0
So both roots are same
⇒ 3t = 1
⇒ t = 1/3
Verification of relationships:
Sum of roots = (1/3)+(1/3) = 2/3 = -(-6)/9 = -b/a
Product of roots = (1/3)*(1/3) = 1/9 = c/a
THANKYOU
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